Q:

solve the sysyem of equations 3x+y=3 x+y=2

Accepted Solution

A:
Answer:{x = 1/2 , y = 3/2Step-by-step explanation:Solve the following system: {3 x + y = 3 | (equation 1) {x + y = 2 | (equation 2) Subtract 1/3 Γ— (equation 1) from equation 2: {3 x + y = 3 | (equation 1) {0 x+(2 y)/3 = 1 | (equation 2) Multiply equation 2 by 3: {3 x + y = 3 | (equation 1) {0 x+2 y = 3 | (equation 2) Divide equation 2 by 2: {3 x + y = 3 | (equation 1) {0 x+y = 3/2 | (equation 2) Subtract equation 2 from equation 1: {3 x+0 y = 3/2 | (equation 1) {0 x+y = 3/2 | (equation 2) Divide equation 1 by 3: {x+0 y = 1/2 | (equation 1) {0 x+y = 3/2 | (equation 2) Collect results: Answer: Β {x = 1/2 , y = 3/2