MATH SOLVE

3 months ago

Q:
# solve the sysyem of equations 3x+y=3 x+y=2

Accepted Solution

A:

Answer:{x = 1/2
, y = 3/2Step-by-step explanation:Solve the following system:
{3 x + y = 3 | (equation 1)
{x + y = 2 | (equation 2)
Subtract 1/3 Γ (equation 1) from equation 2:
{3 x + y = 3 | (equation 1)
{0 x+(2 y)/3 = 1 | (equation 2)
Multiply equation 2 by 3:
{3 x + y = 3 | (equation 1)
{0 x+2 y = 3 | (equation 2)
Divide equation 2 by 2:
{3 x + y = 3 | (equation 1)
{0 x+y = 3/2 | (equation 2)
Subtract equation 2 from equation 1:
{3 x+0 y = 3/2 | (equation 1)
{0 x+y = 3/2 | (equation 2)
Divide equation 1 by 3:
{x+0 y = 1/2 | (equation 1)
{0 x+y = 3/2 | (equation 2)
Collect results:
Answer: Β {x = 1/2
, y = 3/2